Question

find the sum or difference:
(6h^4+4h-10)-(6h^2 +8h-6)

(3b^4+2b-1)+(4b^2+3b-2)
@Aleah.wood0613

Answer 1

2 • (3h^3 - 3h^2 - 2) • (h + 1)

Answer 2

do you know what like terms are ?

Answer 3

god dammit one sec

Answer 4

lol...problems ??

Answer 5

1.) 2(3h^3-3h^2-2)*(h+1)

Answer 6

for the first one....the first thing you do is distribute the negative through the parenthesis

Answer 7

2.) 3b^4 + 4b^2 + 5b - 3

Answer 8

1.) 6h^4 + 4h - 10 - (6h^2 + 8h - 6) --- distribute through the parenthesis
6h^4 + 4h - 10 - 6h^2 - 8h + 6 -- now combine like terms
6h^4 - 6h^2 - 4h - 4 --- now factor
2(3h^4 - 3h^2 - 2h - 2)

Answer 9

2. 3b^4 + 2b - 1 + 4b^2 + 3b - 2 -- combine like terms
3b^4 + 4b^2 + 5b - 3