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can someone check my answer please :)
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Aye!
A^y = x is the exponential form we can change this to logarithmic form by going loga(x) = y
so it would be change from 2^5=32 to log2(32)=5 reading this out is log base 2 of 32 is equal to 5
so is it right?
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c is wrong m8
i literally just wrote the answer out if you would read
OMG I always get pellet wrong >:(
Don't give the direct answer. @sweetburger
pellet*
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i didnt i showed the exponential form
why is it putting the wrong word lol
pellet
Because OS doesn't allow cuss words. @zappy
its A
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why cant i get the answer >:(
A is incorrect....
its D
\[B^x=A ~~is~the~same~as~~\log _{b} A=x\]
Close, but not quite
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@zappy it is \[\log_{2} 32=5\]
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