Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

can someone check my answer please :)

OpenStudy (anonymous):

Aye!

OpenStudy (anonymous):

OpenStudy (sweetburger):

A^y = x is the exponential form we can change this to logarithmic form by going loga(x) = y

OpenStudy (sweetburger):

so it would be change from 2^5=32 to log2(32)=5 reading this out is log base 2 of 32 is equal to 5

OpenStudy (anonymous):

so is it right?

OpenStudy (sweetburger):

c is wrong m8

OpenStudy (sweetburger):

i literally just wrote the answer out if you would read

OpenStudy (anonymous):

OMG I always get pellet wrong >:(

OpenStudy (anonymous):

Don't give the direct answer. @sweetburger

OpenStudy (anonymous):

pellet*

OpenStudy (sweetburger):

i didnt i showed the exponential form

OpenStudy (anonymous):

why is it putting the wrong word lol

OpenStudy (anonymous):

pellet

OpenStudy (anonymous):

Because OS doesn't allow cuss words. @zappy

OpenStudy (anonymous):

its A

OpenStudy (anonymous):

why cant i get the answer >:(

OpenStudy (haleyelizabeth2017):

A is incorrect....

OpenStudy (anonymous):

its D

OpenStudy (haleyelizabeth2017):

\[B^x=A ~~is~the~same~as~~\log _{b} A=x\]

OpenStudy (haleyelizabeth2017):

Close, but not quite

OpenStudy (haleyelizabeth2017):

@zappy it is \[\log_{2} 32=5\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!