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Mathematics 20 Online
OpenStudy (anonymous):

the equation h=16t^2+32t+9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height? What is its maximum height?

OpenStudy (anonymous):

\[h(t)=-16t^2+32t+9\] the max is the vertex

OpenStudy (anonymous):

find the vertex via \(-\frac{b}{2a}\) for the first coordinate plug it in to find the second

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