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Mathematics 22 Online
OpenStudy (anonymous):

Factor 3c3 + 375. –3(c + 5)(c2 – 5c + 25) 3(c + 5)(c2 – 5c + 25) (c – 5)(c2 – 5c + 25) (c + 5)(c2 – 5c + 25)

OpenStudy (hockeychick23):

Ok so first take out a positive 3 not a negative 3, once you take out the 3 it should look like this: Step 1: 3c^3+375=3(c^3+125) Next you can divide everything by 3 and factor out whats in the parentheses Step 2: (c+5)(c^2-5c+25)

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