Question

If f(x) is differentiable for the closed interval [−4, 0] such that f(−4) = 5 and f(0) = 9, then there exists a value c, −4 < c < 0 such that

Answer 1

f(c)=0
f'(c)=0
f(c)=1
f'(c)=1

Which is the answer and how do you do it?