Question

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Answer 1

For similar figures,
(ratio of similar sides)^2 = (ratio of the area)

Answer 2

So
\[\text{Area of ABCD : Area of EFGH} = (\text{AB:EF})^2\]

Answer 3

1:6)^2 ?

Answer 4

perimeter EFGH = 108
ABCD perimeter= 18

Answer 5

you got 108 by multiplying 18 with the scale factor 6 ?

Answer 6

that looks good!

Answer 7

18 * 6 = 108 :)

Answer 8

i think we can say all "corresponding lengths" scale by same factor when shapes are similar

perimeter is also a length