Question

Let f(x) = 27x5 - 33x4 - 21x3 and g(x) = 3x2. Find f of x over g of x

9x2 - 11x - 7
9x2 + 11x + 7
9x3 - 11x2 - 7x
9x3 + 11x2 + 7x

Answer 1

@ganeshie8

Answer 2

here is a common factor of 3x^2 in each term
leaving 9x^3 - 11x^2 - 7x

Answer 3

@phi

Answer 4

so c @burn23

Answer 5

yes C

Answer 6

can you help we couple more :)

Answer 7

sure :)

Answer 8

Divide 3x2 - 11x - 4 by x - 4.

x + 1
x - 23
3x + 1
3x - 23

Answer 9

3x2–11x–4/ x–4=(x−4)(3x+1)/x−4=3x+1

Answer 10

Let f(x) = 8x3 - 28x + 61 and g(x) = 2x + 5. Find f of x over g of x.

4x2 + 10x + 34 + 116 over quantity of 2 x plus 5
4x2 + 10x + 34 + quantity of 2 x plus 5 over 116
4x2 - 10x + 11+ quantity of 2 x plus 5 over 6
4x2 - 10x + 11+ 6 over quantity of 2 x plus 5

Answer 11

@burn23

Answer 12

4x^2-10x+11+6/2x+5

Answer 13

Divide 36x3 - 96x2 + 48x by 12x.

3x2 - 8x + 4
3x2 + 8x - 4
3x3 - 8x + 4
3x3 + 8x - 4

Answer 14

@burn23