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A rectangle is inscribed in a circle of radius r. If the rectangle has length 3x, write the area of the rectangle as the product of two functions.
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|dw:1420610260087:dw| use Pythagoras
and then would i combine it with pie(r^2)?
asked about area of rectangle not the circle,so area = height X width.
oh ok so then it would end up as (2r)^2 - (3x)^2 = a
then i would solve for a?
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\[a = \sqrt{(2r)^{2} - (3x)^{2}}.\] and then area = a X 3x
ok thank you so much
ur welcome
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