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Mathematics 22 Online
OpenStudy (anonymous):

PLS HELP DUE TOMORROW

OpenStudy (anonymous):

OpenStudy (stamp):

As you know from your textbook, notes, and lecture, direct variation is defined as y = kx Where k is the constant of variation. Your posted question informs us that when y = 9, x = -3. Use this knowledge to solve for the missing link, your constant of variation k. 9 = k (-3) 9 = -3k k = -3 So, y = kx can be expressed as: ??

OpenStudy (anonymous):

how do i find x

OpenStudy (freckles):

you have y=kx and @stamp showed you how to find k so replace k with what he found. then use the value given for y to find x.

OpenStudy (anonymous):

so what would the equation i need to find x look like

OpenStudy (freckles):

the equation given by both stamp and I y=kx

OpenStudy (freckles):

stamp found the constant k k will always be -3 for any point (x,y)

OpenStudy (freckles):

so replace k in y=kx with -3

OpenStudy (freckles):

then use the value given for y to find x

OpenStudy (anonymous):

y=-3+x

OpenStudy (freckles):

where do you get the sum from

OpenStudy (freckles):

you y=kx y=k times x times doesn't turn into plus

OpenStudy (anonymous):

y=-3x

OpenStudy (freckles):

y=-3x

OpenStudy (anonymous):

y=-3x +3 +3 3y=x

OpenStudy (freckles):

you can't undo multiplication by addition also your objective is to find x given y=18

OpenStudy (anonymous):

18=-3x -3 -3 -6=x

OpenStudy (freckles):

bingo! :)

OpenStudy (anonymous):

thanks can you help with another please

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