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OpenStudy (anonymous):
OpenStudy (stamp):
As you know from your textbook, notes, and lecture, direct variation is defined as
y = kx
Where k is the constant of variation.
Your posted question informs us that when y = 9, x = -3. Use this knowledge to solve for the missing link, your constant of variation k.
9 = k (-3)
9 = -3k
k = -3
So, y = kx can be expressed as: ??
OpenStudy (anonymous):
how do i find x
OpenStudy (freckles):
you have y=kx
and @stamp showed you how to find k
so replace k with what he found.
then use the value given for y to find x.
OpenStudy (anonymous):
so what would the equation i need to find x look like
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OpenStudy (freckles):
the equation given by both stamp and I
y=kx
OpenStudy (freckles):
stamp found the constant k
k will always be -3 for any point (x,y)
OpenStudy (freckles):
so replace k in y=kx with -3
OpenStudy (freckles):
then use the value given for y to find x
OpenStudy (anonymous):
y=-3+x
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OpenStudy (freckles):
where do you get the sum from
OpenStudy (freckles):
you y=kx
y=k times x
times doesn't turn into plus
OpenStudy (anonymous):
y=-3x
OpenStudy (freckles):
y=-3x
OpenStudy (anonymous):
y=-3x
+3 +3
3y=x
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OpenStudy (freckles):
you can't undo multiplication by addition
also your objective is to find x given y=18