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if csc theta = -5/3 and theta has its terminal side in quadrant III, find the exact value of tan 2 theta.
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I would do a doodle of a right triangle in quadrant 3 with csc(theta)=-5/3
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label the sides with the correct measurement
\[\tan(2 \theta)=\frac{\sin(2 \theta)}{\cos( 2 \theta)}=\frac{ 2 \sin(\theta) \cos(\theta)}{\cos^2(\theta)-\sin^2(\theta)}\]
then you can find tan(2 theta) by using your triangle
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