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find the exact value fir tan(6pi) please i need this to be explained
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Did you try tan(6pi ) = sin(6pi) / cos(6pi)
since tan x = sin x / cos x
where did you get that from?
thats the definition of tan x
trig functions
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|dw:1420682872461:dw| Trig definitions: \[\sin \theta = \frac{ A }{ C } \rightarrow A = C \sin \theta \]\[\cos \theta = \frac{ B }{ C } \rightarrow B = C \cos \theta\]\[\tan \theta = \frac{ A }{ B } = \frac{ C \sin \theta }{ C \cos \theta } = \frac{ \sin \theta }{ \cos \theta }\]
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