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Mathematics 18 Online
OpenStudy (anonymous):

Check my answer? Solving variables?

OpenStudy (anonymous):

I got 3

OpenStudy (alexandervonhumboldt2):

so (k+1)*5=4*(2k-1)

OpenStudy (alexandervonhumboldt2):

5k+5=8k-4

OpenStudy (alexandervonhumboldt2):

-3k=-9

OpenStudy (alexandervonhumboldt2):

k=3

jimthompson5910 (jim_thompson5910):

Checking the answer: Plug k = 3 into the original equation (replace every k with 3 and evaluate) If you get a true result, then the answer is confirmed \[\Large \frac{k+1}{2k-1} = \frac{4}{5}\] \[\Large \frac{3+1}{2(3)-1} = \frac{4}{5}\] \[\Large \frac{3+1}{6-1} = \frac{4}{5}\] \[\Large \frac{4}{5} = \frac{4}{5} \ \ {\color{green}{\checkmark}}\] The last equation above is true So the answer is confirmed

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