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Check my answer? Solving variables?
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I got 3
so (k+1)*5=4*(2k-1)
5k+5=8k-4
-3k=-9
k=3
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Checking the answer: Plug k = 3 into the original equation (replace every k with 3 and evaluate) If you get a true result, then the answer is confirmed \[\Large \frac{k+1}{2k-1} = \frac{4}{5}\] \[\Large \frac{3+1}{2(3)-1} = \frac{4}{5}\] \[\Large \frac{3+1}{6-1} = \frac{4}{5}\] \[\Large \frac{4}{5} = \frac{4}{5} \ \ {\color{green}{\checkmark}}\] The last equation above is true So the answer is confirmed
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