Question

find the values for q that satisfy the equation

Answer 1

use this\[0 \leq q \leq 2p\]
for this
\[\sqrt[2]{2}\sin q+2=0\]

Answer 2

sure you can derive it from sin^2 + cos^2 = 1, but it's basically been done hundreds of times before

Answer 3

im not sure what u mean

Answer 4

do you have choices?

Answer 5

p,2p
\[\frac{ 3\pi }{ 4 },\frac{ 5\pi }{ 4 }\]
\[\frac{ \pi }{ 4 },\frac{ 3\pi }{ 4 }\]
\[\frac{ 5\pi }{ 4 },\frac{ 7\pi }{ 4 }\]