Question

A rectangle has a perimeter of 34 cm2 and an area of 52cm2 its length is 5 more than twice its width write and solve a system of equations to find the dimensions of the rectangle

Answer 1

please help will give medal.

Answer 2

@eric_d

Answer 3

p= 34
A= 52 cm
L=2w+5
w+w+2w+5+2w+5=P
So now try and add up all the w's and all the numbers and see what you get

Answer 4

thank you. it is 6w+10=p?

Answer 5

correct :) and you know that p is 34 so you can plug that in:
34= 6w+10
now subtract 10 from both sides

Answer 6

now were just doing simple algebraic equations 24=6w and that makes it be 4=w

Answer 7

correct!(:

Answer 8

so how would it be answered?
the answer would be the unsimplified equation of 6w+10=p?
I just had trouble with the wording it really conufsed me

Answer 9

or would the answer be 4=w?

Answer 10

ok so since its asking for all the dimensions and you know that 1 width=4 and you have 2 widths that would total 8, so you subtract 34-8= 26, and you have to split that between 2 lengths so divided by 2, each length is 13 and each width is 4, those are your dimensions

Answer 11

but the answer is just the equation it doesnt need to be answered, at leas the way i read it, from what i read I just need to know which equation it the answer

Answer 12

ok what are your choices?

Answer 13

nvm it does need to be solved

Answer 14

ok

Answer 15

so um. I really am unsure what it is.

Answer 16

hello?

Answer 17

what are you trying to figure out? i thought you wanted the dimensions