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PLEASE HELP!! Solve for extraneous solution sqrt. sqrt. x+25 = sqrt. x+5
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u need help solving it
yes please! D: this is the last equation
kay, thank you ^^ I'll try.. It confuses me because theres double square roots, like this \[\sqrt{\sqrt{x+25}}=\sqrt{x+5}\]
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ummm i want u too really underdstanf it did it help
tell me its k
http://www.algebra.com/algebra/homework/Radicals/Radicals.faq.question.717301.html
okay that last link helps! Thank you!!!
ur welcome i am only in 5th grade gifted class
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and i medal fan u
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