Question

How do I solve x2 + 4x - 12 = 0?

Answer 1

you put 0 in for x

Answer 2

The options were

x = 2, x = -6
x = -2, x = -6
x = 3, x = -4
x = -3, x = 4

And I was wondering how to get one of these

Answer 3

you put those in for x til you get the answer

Answer 4

do you know the formula
\(x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\)

Answer 5

Sorta

Answer 6

in the equation \( \color {red}{1}x^2+\color{blue}{4}x \color{green}{-12}=0\)
you have \(\color {red}{a=1}\), \(\color{blue}{b=4}\) and \(\color{green}{c=-12}\)
just replace them to the formula above to get 2 values of x. Those must be one of the options.

Answer 7

OOOOOOoOOOOOOOoookkkkkK gotcha

Answer 8

Thank you

Answer 9

yw