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If there is a 80% chance of rain and a 70% chance of wind and rain, what is the probability that it is windy, given that it is rainy? Round your answer to the nearest percent. A 63 B 38 C 13 D 88
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Since P(rain)=70%, P(rain & wind)=80% and given it rains, then by definition of conditional probability P(wind|rain)=P(wind \(\cap\) rain)/P(rain) and recall that P(wind \(\cap\) rain) = P(rain \(\cap\) wind) and that P(wind|rain) reads as "Probability of wind given that it is rainy".
i think you have it backward it 70% rain and wind and 80% rain
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