Question

Help with algebra 2 question please?
Evaluate log2 (1/8).

I know the answer is -3....I just don't know how to get the answer.

Answer 1

log2 (1/8) is basically asking:
2^(x)=1/8
Well 2^3=8
So if you make the exponent negative, you'll get 1/8
So that's why the answer is -3 :)
Hope that helps!

Answer 2

\(\log_b b^n = n\)
Write 1/8 as a power of 2.
Then the log of 1/8 is simply the exponent that 2 is raised to.

Answer 3

Bruhhh thank you so much. :)

Answer 4

No prob! :)