help please!
[9.01] What is the value of the coefficient "b" when the quadratic equation y = (3x + 2)(2x − 1)is written in standard form? please explain
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myininaya (myininaya):
so multiply (3x+2)(2x-1)
and i bet you are looking for the coefficient of x
OpenStudy (anonymous):
i says coefficient of b?
myininaya (myininaya):
there is no b...
ax^2+bx+c
I think they are calling b the coefficient of x
myininaya (myininaya):
you need to expand (3x+2)(2x-1) by multiplying
OpenStudy (anonymous):
how do i do that?
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myininaya (myininaya):
multiply?
myininaya (myininaya):
have you heard of the distributive property?
(a+b)(c+d)
=a(c+d)+b(c+d)
OpenStudy (anonymous):
how do i multipy them together? because theres two x's
myininaya (myininaya):
distribute and add like terms
OpenStudy (anonymous):
im so confused
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myininaya (myininaya):
example
\[(ax+b)(cx+d) \\
=ax(cx+d)+b(cx+d) \\
=ax \cdot cx + ax \cdot d+b \cdot cx +b \cdot d \\
=ac x^2+ax d+bc x+bd \\
=acx^2+(ad+bc)x+bd\\
\text{ the coefficent } \text{ of x here is } ad+bc\]
OpenStudy (anonymous):
so... (3x+2)(2x+1)?
myininaya (myininaya):
you need to first multiply
myininaya (myininaya):
have you done that yet
myininaya (myininaya):
you can follow my example if you want
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OpenStudy (anonymous):
im lost
OpenStudy (anonymous):
multiply what
OpenStudy (anonymous):
@myininaya
myininaya (myininaya):
(3x+2)(2x+1)
follow what I said...
the first line of what I said is
3x(2x+1)+2(2x+1)
now use the distributive property on both like I did in my third line
OpenStudy (anonymous):
im still lost
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OpenStudy (anonymous):
@myininaya use more simply terms you use such big words
myininaya (myininaya):
distributive property?
myininaya (myininaya):
this is the name of the property
myininaya (myininaya):
a(b+c)=ab+ac
OpenStudy (anonymous):
i got it. its 1
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