Question

Please help me with algebra 2!!!

Answer 1

\[\frac{ 3 }{ \frac{ 3-x }{ x } +1}\]

Answer 2

Help me simplify!!!

Answer 3

\[\frac{3}{\frac{3-x}{x}+1}=\frac{3}{\frac{3}{x}}=x \]

Answer 4

\[\frac{ 3 }{ \frac{ 3-x }{ x } +1}=\frac{ 3 }{ \frac{ 3-x }{ x } +1}\times \frac{x}{x}=\frac{3x}{3-x+x}\]
\[=\frac{3x}{3}=x\]