Question

An expression is shown below:

3x^3y + 12xy - 3x^2y - 12y

Part A: Rewrite the expression so that the GCF is factored completely.

Part B: Rewrite the expression completely factored. Show the steps of your work.

Part C: If the two middle terms were switched so that the expression became 3x^3y - 3x^2y + 12xy - 12y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning.

Answer 1

GCF?

Answer 2

I believe that the GCF would be 3y for this expression

Answer 3

Well factoring it out we would get... 3y ( x^3 + 4x - x^2 - 4 )

Answer 4

Thats for part B

Answer 5

Okay, but I do know how to factor but I am not very good at it so if you can, can you show me the work so I can better understand this?

Answer 6

Would u like a post that could help possibly or just me?

Answer 7

3x3y+12xy-3x2y-12y
=9xy+12xy-6xy-12y
=21xy-6xy-12y
=15xy-12y
=3y(5x-4)
If its me here is A

Answer 8

Does this help make sense?

Answer 9

math u there?

Answer 10

Um sort of. I am honestly a little confused though, how did you get 9xy for the first term?

Answer 11

3x3

Answer 12

its 3x^3y actually

Answer 13

For C here is the answer to that, =3y(x^3+x^2+4x-4)
=3y(x^2(x-1)+4(x-1))
=3y(x^2+4)(x-1)

Answer 14

I forgot to put in the ^ when I posted the question

Answer 15

Yep ;)

Answer 16

Ok but this is something that I am normally good at but keep forgetting. 3x^3y would be 27xy I think...

Answer 17

Well go with your gut.

Answer 18

Because 3^3 = 27, so I guess 3x^3y would be 27xy but I am not entirely sure

Answer 19

As i said before. Go with your gut. I want you to be happy with your answers.

Answer 20

Lol okay. Well here is how I am solving it right now:

3x^3y + 12xy - 3x^2y - 12y
27xy + 12xy - 9xy - 12y
39xy - 9xy - 12y
30xy - 12y

Answer 21

Looks fine to me. But 1 persons information really isnt enough, i would tag some people in here. See what they say ^-^

Answer 22

Hmm, okay. One min

@ganeshie8 @SolomonZelman @dan815

Answer 23

Okay I might have tagged too many people.

Answer 24

I see that.

Answer 25

@iambatman

Answer 26

So no one is coming to my rescue. As always. -_-

Answer 27

@sleepyjess

Answer 28

Im sorry...

Answer 29

That seems to be the case with me as well.

Answer 30

What are you sorry for? It's perfectly fine. You helped me, it's just that I need a little more help because I can't remember some things.

Answer 31

I don't know what to do with terms like 3x^3y

Answer 32

Ah. Well. I really am sorry because i really have to get back to my test XD. Im helping people while testing.

Answer 33

So far your my 2nd

Answer 34

\[3x ^{3}y + 12xy - 3x^2y - 12y\]

Answer 35

Thank you though! I really appreciate it

Answer 36

Ill just sit ehre and try to figure it out while I wait for someone. :).

Answer 37

Sorry i cant help any further. I dont plan on getting locked out of my test anytime soon.

Answer 38

here *

Answer 39

Are you in flvs?

Answer 40

Why yes i am.

Answer 41

Could you use a logarithm ?

Answer 42

Me too

Answer 43

Ooh I am too lol
But actually I dont think log could work

Answer 44

I don't even know what a logarithm is. But I will just review some videos from my lessons. I should just try to figure it out myself. But If I am really struggling, I will come back here

Answer 45

Thanks for your help @DivineSolar

Answer 46

Heres a medal for you actually willing to help a stubborn person such as myself. lol. :)

Answer 47

Bye. :)

Answer 48

Oh you haven't learned logs yet?

Answer 49

See ya. Sorry for the luck we both have XD

Answer 50

Ohhh waaait, I figured it out!!

Answer 51

They're just trying to throw you off because they're evil.

3x^3y +12xy-3x^2y -12y
Group themmm, then it will be easier to factor.
(3x^3y +12xy)+(-3x^2y -12y)
You factor 3x from the first and -3 from the second and it works!
If you need me to work the whole thing out, lemme know