Question

@DanJS

Answer 1

@Jhannybean @poopsiedoodle

Answer 2

@Nnesha

Answer 3

Average value: \(\dfrac{f(b)-f(a)}{b-a}\) Right?

Answer 4

yes!

Answer 5

\[\dfrac{\dfrac{1}{2e}-\dfrac{1}{e}}{2e-e} \cdot \frac{e}{e} = \frac{\dfrac{1}{2}-1}{e(e)} =-\frac{\dfrac{1}{2}}{e^2} = -\frac{1}{2e^2}\]

Answer 6

\[\large \color{red}{\checkmark}\]

Answer 7

yay , thanks(:

Answer 8

mmhmm.