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\[\log(x)=y\iff 10^y=x\]
Convert to exponential form and then solve. The base of the log is understood to be 10. \[10^3=2x+3\]
start with \[2x+3=10^3\] and solve for \(x\)
you should be able to go from \[\log_b(x)=y\] to \[b^y=x\] and back quickly when you don't see a base, it is assumed to be ten
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