Question

@perl

Answer 1

first one is correct , c = 2

Answer 2

:)

Answer 3

actually it might be better if we used this equation
http://www.ugrad.math.ubc.ca/coursedoc/math100/notes/diffeqs/cool.html

Answer 4

T(t) = Ta + (To - Ta) e^(-kt)

Ta = ambient or room temp
To = temp of object at time zero

Answer 5

so here
Ta = 70
To = 100

T(t) = 70 + (100 - 70) e^(-kt)

and we need to find k

Answer 6

the question doesnt make sense, it says egg and then coffee ?

Answer 7

yeah i didnt notice it said coffee.. that really doesnt make sense

Answer 8

if we find k, it would be 79?

Answer 9

what would be my best guess here?

Answer 10

T(t) = 70 + 30 e^(-kt)

now we are given
T(1) = 90

90 = 70 + 30e^(-k*1)

20 = 30 e^(-k*1)
(20/30) = e^(-k*1)

ln(20/30) = -k*1

k = -ln(20/30)

Answer 11

T(t) = 70 + 30e^(-.40546 * t )

T(4) = 75.925925..

to the nearest degree is 76

Answer 12

thank you(: i only have 2 more to check(: