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@perl
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i got 16
distance should always be positive
distance = integral | v(t)|
oh 3.00
displacement = integral v(t) , note that i used absolute value bars
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ohhh!
and the first one was correct?@perl
displacement for first 3 seconds is 3 http://www.wolframalpha.com/input/?i=integrate+%28-t^2%2B4%29%2C+t%3D+0..3 distance for first 4 seconds is 16: http://www.wolframalpha.com/input/?i=integrate+abs%28-t^2%2B4%29%2C+t%3D+0..4
yay i got it right, thanks(:
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