Question

find area of rectangle

Answer 1

@OOOPS

Answer 2

what's the formula man?

Answer 3

u mean the formula for the problem?

Answer 4

Yes

Answer 5

a ^m-n=

Answer 6

area of rectangle?

Answer 7

duh xd area= lxw

Answer 8

l*w

Answer 9

how do i turn \[\sqrt[3]{81}\] into a fraction

Answer 10

:)
now you have l as 81 cubeth root
w as 3 to the power 2/3

Answer 11

can you express 81 interms of 3? like 3 to the power something?

Answer 12

ummmm 81 1/3

Answer 13

thats wrong isn't it

Answer 14

what?, \[ 3^x = 81 \ \ \ x \ = \ ? \]

Answer 15

divide 81 by 3, see how many times it can divisible by 3,
see 9 = 3^2 that's because 9 can be divisible by 3 two times.

Answer 16

u two r doing great :)

Answer 17

27

Answer 18

okay 3*27 = 81, still 27 can be divided by 3 right?
divide until you left with 1.

Answer 19

9

Answer 20

3 overall

Answer 21

3*3 = 9
3*3 = 9
9*9 = 81 = 3*3*3*3 four times right?

Answer 22

oh so 3^4

Answer 23

hmm, now do the l*w thing

Answer 24

wait do 3^4 * what

Answer 25

\[\sqrt[3]{81} \ = \sqrt[3]{3^4} \ = 3^{4/3}\]

Answer 26

we have l as 3^[4/3] right?
and w as 3 ^[2/3]
so do l*w

Answer 27

3 4/3 * 3 2/3

Answer 28

lol yes what u wrote

Answer 29

hmm now you know the formula
\[a^m + a^n = a^{m+n}\] right?

Answer 30

yes

Answer 31

9 8/3?

Answer 32

@fatZak from around 15minutes what are you doing buddy?

Answer 33

Area of a rectangle = lenght x width
\[Area= \sqrt[3]{81}\times3^{\frac{2}{3}}\]
\[Area = 81^{\frac{1}{3}}\times3^{\frac{2}{3}}\]
\[Area = 3^{4\times\frac{1}{3}}\times3^{\frac{2}{3}}\]
\[Area = 3^{\frac{4}{3}}\times3^{\frac{2}{3}}\]\[Area = 3^{\frac{4}{3}+\frac{2}{3}}\]\[Area = 3^{\frac{6}{3}}\]\[Area = 3^{2}\]\[Area = 9\]

Answer 34

\[3^{4/3} \ + 3^{2/3} \ = 3^{4/3 + 2/3} \ = 3^{6/3} \ = 3^2 \]

Answer 35

@fatZak good job dude :)

Answer 36

thanks