Question

im helping my brother his assignment! can you help me too?

solve for the derivative og the folowing function implicitly

x^3 - 3x^2y + 3xy^2 = 12

Answer 1

\[3x^2-3(2xy+3x^2y')+3(y^2+2xyy')=0\] os a start

Answer 2

ok

Answer 3

then a bunchy of algebra to solve for \(y'\)

Answer 4

ok

Answer 5

@misty1212 whats next?

Answer 6

algebra that your brother can do

Answer 7

@triciaal how can i apply the algebra? in that question?

Answer 8

@zepdrix help

Answer 9

@dtan5457 help

Answer 10

if you didn't post the same question twice we would get there faster
I am waiting for your brother to see if he has any questions before moving on remember?

Answer 11

to apply the algebra means to collect like terms and simplify

Answer 12

@triciaal sorry ms. his crying right now.

Answer 13

all i can do is to help him.

Answer 14

so please help.

Answer 15

he needs to take a break yes
crying is not going to get to the solution
tell him to take some deep breathes get himself together and come back in 5 mins

Answer 16

you might also want to close the other question. If you don't understand enough to pass it on to him then as much as you want to help it would not be helping him because he won't know what is before him.

Answer 17

ok ok, ill call him right now

Answer 18

he has to be ready

Answer 19

good you are on this site. People are here to help.

Answer 20

@ayo123 help :)

Answer 21

sorry for taking this long

x^3 - 3x^2y + 3xy^2 = 12
3X^2 -6xy-3X^2(dy/dx) + 3y^2 +6xy(dy/dx) =0
rearranging,
3X^2 + 3y^2 -6xy -3X^2(dy/dx) +6xy(dy/dx) =0
collecting like terms
3X^2 -6xy + 3y^2 = 3X^2(dy/dx) - 6xy(dy/dx)
3(X^2 -2xy + y^2) = (3X^2 -6xy) (dy/dx)
(dy/dx) = (3 (X^2 -2xy + y^2) ) / (X^2 -2xy) (3)
(dy/dx) = (X^2 -2xy + y^2)/ (X^2 -2xy)
(dy/dx) =( (x-y)(x-y) ) / ( (x-2y)(x) )