Question

What are the solutions of the quadratic equation? 4x^2-9x-9=0

And can you show me the steps?

Answer 1

\[4x ^{2} -9x -9 = 4x ^{2} -12x + 3x -9=4x(x-3)+3(x-3) =(4x+3)(x+3)\]

Answer 2

i splited it as (-12) and 3 because 4*(-9)= -36 which can also be written as -12*3=-36

Answer 3

and since term with "x" is negative .. therefore 12 is taken as negative.... if it would have been positive.... 3 would have been taken negative...

Answer 4

(4x + 3)(x - 3)

is his final he made a mistake in writing the final answer
x-3 instead of x+3