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OpenStudy (batman*):
^-1
OpenStudy (dtan5457):
please state what the function is.
OpenStudy (anonymous):
x+3/x-2
OpenStudy (anonymous):
and even how to find domain and range
OpenStudy (dtan5457):
alright, give me a minute as i show my work
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OpenStudy (anonymous):
thank you
OpenStudy (dtan5457):
alright, so what you do with
y=x+3/x-2
switch the letters to get
x=y+3/y-2
1. you take out the denominator
multiply x-2 by y and you get
yx-2x=y+3
2. isolate y by subtracting it, and isolate x and the whole number to another side
yx-y=2x+3
3. factor y to get
y(x-1)=2x+3
now your final inverse would be
y=2x+3/x-1
OpenStudy (dtan5457):
@Sadworld @mathstudent55 @AriPotta
can you guys check this for me
OpenStudy (anonymous):
ya
wat
OpenStudy (anonymous):
I second @dtan5457
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OpenStudy (dtan5457):
alright cool, thanks. just making sure
OpenStudy (anonymous):
how to do simpler expression of 2ln sqaureroot e
OpenStudy (anonymous):
\[\sqrt[e]{2}?\]
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
2 ln squareroot e
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OpenStudy (anonymous):
|dw:1421189810863:dw|
OpenStudy (anonymous):
I got 1.
OpenStudy (anonymous):
how u solved it
OpenStudy (anonymous):
calculator :/
OpenStudy (anonymous):
i forgot as i did this 4 years before
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OpenStudy (anonymous):
ok
thank you bae
OpenStudy (anonymous):
Same, been ages for me too.
OpenStudy (anonymous):
do u know how to do without calci
OpenStudy (anonymous):
Nope :/ You can try asking one of the greens for help.