Suppose that the Toronto Blue Jays (baseball team, I guess) face the New York Yankees in the division final. In this best-of-five series, the winner is the first team to win 3 games. The games are played in Toronto and in New York, with Toronto hosting the first, second, and if needed, fifth geams. The consensus among experts is that Toronto has a 65% chance of winning at home and a 40% chance of winning in New York. What is the chance of Toronto winning in three straight games?
a) Construct a tree diagram to illustrate all possible outcomes

Question

Suppose that the Toronto Blue Jays (baseball team, I guess) face the New York Yankees in the division final. In this best-of-five series, the winner is the first team to win 3 games. The games are played in Toronto and in New York, with Toronto hosting the first, second, and if needed, fifth geams. The consensus among experts is that Toronto has a 65% chance of winning at home and a 40% chance of winning in New York. What is the chance of Toronto winning in three straight games? 
a) Construct a tree diagram to illustrate all possible outcomes

misty1212 · Answer

HI!

misty1212 · Answer

i think all you need to do is multiply

misty1212 · Answer

$$.65\times .65\times .45$$ with a calculator