Question

.Solve the following trigonometeric equation on the interval [0,2pi).
3cos x = cos x -1

a) pi/2, 4pi/3
b) pi/2, 2pi/3
c) 2pi/3, 4pi/3
d) 4pi/3, 5pi/3

Solvw thw following trigonometric equation on the interval [0, 2pi)

a) 5pi/3, 7pi/3, 2pi/3, 4pi/3
b) pi/3, 4pi/3
c) pi/3, 5pi/3
d) 0, pi/3, pi, 5pi/3

Answer 1

HI!

Answer 2

start with
\[2\cos(x)=-1\] so
\[\cos(x)=-\frac{1}{2}\] and solve that !