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Mathematics 8 Online
OpenStudy (dtan5457):

Solve using LCD. Check for extraneous solutions

OpenStudy (dtan5457):

\[\frac{ 1 }{ 2x }+\frac{ 3 }{ x+7 }=\frac{ -1 }{ x }\]

OpenStudy (dtan5457):

@Nnesha

OpenStudy (dtan5457):

i was gonna make the denominator the same for the first 2, but doesn't that ruin the equation, as you need to make all 3 since there is a = sign?

Nnesha (nnesha):

solve left side first

OpenStudy (dtan5457):

oh wait what am i thinking just multiply first one by x+7 and other by 2x

OpenStudy (dtan5457):

right?

Nnesha (nnesha):

perfect and your denominator are different so final denominator would be both 2x(x+7)

Nnesha (nnesha):

and yes you are right multiply first one top part by x+7 and 2nd by 2x

OpenStudy (dtan5457):

so first 2 i got 7x+7 2x(x+7)

OpenStudy (dtan5457):

<<fractioned

Nnesha (nnesha):

right

Nnesha (nnesha):

now you can cross multiply

Nnesha (nnesha):

distribute bracket by 2x

OpenStudy (dtan5457):

-2x^2-14x=7x^2+7x

Nnesha (nnesha):

yes now solve :)

OpenStudy (dtan5457):

9x^2=21x?

OpenStudy (dtan5457):

*-21x

Nnesha (nnesha):

right

OpenStudy (dtan5457):

oh right, yea

Nnesha (nnesha):

so 7x+14x = 21x is right

OpenStudy (dtan5457):

yea

OpenStudy (dtan5457):

now what?

Nnesha (nnesha):

-2x^2-14x=7x^2+7x subtract 7x^2 both side then you should get what x^2 ??

OpenStudy (dtan5457):

-9x^2

Nnesha (nnesha):

yes right

OpenStudy (dtan5457):

i forgot how to add

Nnesha (nnesha):

nope you are tired

Nnesha (nnesha):

:D :)

OpenStudy (dtan5457):

yea...very true. now what should i do?

Nnesha (nnesha):

|dw:1421206095752:dw| subtract 21x both side then find gcf

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