Mathematics
8 Online
OpenStudy (dtan5457):
Solve using LCD. Check for extraneous solutions
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OpenStudy (dtan5457):
\[\frac{ 1 }{ 2x }+\frac{ 3 }{ x+7 }=\frac{ -1 }{ x }\]
OpenStudy (dtan5457):
@Nnesha
OpenStudy (dtan5457):
i was gonna make the denominator the same for the first 2, but doesn't that ruin the equation, as you need to make all 3 since there is a = sign?
Nnesha (nnesha):
solve left side first
OpenStudy (dtan5457):
oh wait what am i thinking just multiply first one by x+7 and other by 2x
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OpenStudy (dtan5457):
right?
Nnesha (nnesha):
perfect
and your denominator are different so final denominator would be both 2x(x+7)
Nnesha (nnesha):
and yes you are right multiply first one top part by x+7 and 2nd by 2x
OpenStudy (dtan5457):
so first 2 i got 7x+7
2x(x+7)
OpenStudy (dtan5457):
<<fractioned
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Nnesha (nnesha):
right
Nnesha (nnesha):
now you can cross multiply
Nnesha (nnesha):
distribute bracket by 2x
OpenStudy (dtan5457):
-2x^2-14x=7x^2+7x
Nnesha (nnesha):
yes now solve :)
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OpenStudy (dtan5457):
9x^2=21x?
OpenStudy (dtan5457):
*-21x
Nnesha (nnesha):
right
OpenStudy (dtan5457):
oh right, yea
Nnesha (nnesha):
so 7x+14x = 21x is right
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OpenStudy (dtan5457):
yea
OpenStudy (dtan5457):
now what?
Nnesha (nnesha):
-2x^2-14x=7x^2+7x
subtract 7x^2 both side then you should get what x^2 ??
OpenStudy (dtan5457):
-9x^2
Nnesha (nnesha):
yes right
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OpenStudy (dtan5457):
i forgot how to add
Nnesha (nnesha):
nope you are tired
Nnesha (nnesha):
:D :)
OpenStudy (dtan5457):
yea...very true. now what should i do?
Nnesha (nnesha):
|dw:1421206095752:dw|
subtract 21x both side
then find gcf