Question

Can someone please help me with this question? medal for anyone who helps :)

If y varies inversely as the square of x, and y=1/8 when x=1, find y when x=5.

Answer 1

um dats hard

Answer 2

haha i know

Answer 3

86 i tink

Answer 4

...ill help

Answer 5

how did you get 86 @luckycoins888 ? that's not one of the options for the question but i appreciate the help :)

Answer 6

please help @crazychickengirl123 !!

Answer 7

what are the options?

Answer 8

that wold be d

Answer 9

i meant d

Answer 10

how did you get that though? i wanna know so i can do the next question myself :)

Answer 11

internet

Answer 12

use the internet

Answer 13

i did...i couldn't find the exact answer.

Answer 14

sorry but plz use the internet i have to go :(

Answer 15

ok, thanks for the help!

Answer 16

I'm sorry but @sleepyhead314 can help :)

Answer 17

the statement "y varies directly as x" can be written as
y = kx, where k is the variation constant

we are given y=12 when x=2, so
12 = 2k
k=6,
so the variation constant is 6 and the equation is
y = 6x

Answer 18

*sleepy sorry if I sound confusing*
but it says inversely
so y = k/x
where k is a constant that we have to find

Answer 19

temporarily plug in y=1/8 and x= 1
for y and x into y = k/x and solve for k

so 1/8 = k/1 solve for k

Answer 20

once you get k
y = (k)/x
plug in k
then plug in x = 5
and solve for y

Answer 21

@crazychickengirl123 it says "inversely" not directly...

Answer 22

shhhhhhh... im sleeping