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sin(2arctan(4))=? I used to just make a triangle and evaluate it from there but not sure how to go about that with the "2". How should I solve this?
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Let \(\Large \theta = \arctan(4)\) Use an identity to get \[\Large \sin(2\arctan(4)) = \sin(2\theta)\] \[\Large \sin(2\arctan(4)) = 2\sin(\theta)\cos(\theta)\] \[\Large \sin(2\arctan(4)) = 2\sin(\arctan(4))\cos(\arctan(4))\]
Hopefully you see what to do from here
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