Question

what is the procedure??
Log2(3-7x)=log2 (6x2)

Answer 1

hey!
\[\log_{2} [3-7x]=\log_{2}[6x^2] \Longrightarrow 3-7x=6x^2 \]

Answer 2

we have the property:
\[\log_{a} (b)=\log_{a}(c) \Longrightarrow b=c \]

Answer 3

now you just need to solve the quadratic equation
\(\large 6x^2+7x-3=0\)

Answer 4

ok thanks

Answer 5

wlc!

Answer 6

just try the quadratic formula