Sketch a graph of a quadratic function: y = ax^2 + bx +c where a0, b^2-4ac

Question

Sketch a graph of a quadratic function:
y = ax^2 + bx +c where a>0, b^2-4ac<0

freckles · Answer

a>0 means the parabola will be opened up a<0 means the parabola will be opened down b^2-4ac=0 means you will have one x-itnercept b^2-4ac>0 means you will have two x-intercepts b^2-4ac<0 means you will have no x-intercepts

anonymous · Answer

Gotcha! So it will open up and there are no x-intercepts so how will i graph that on a general graph?

freckles · Answer

you would graph a parabola that is open up 
and does not go through the x-axis

freckles · Answer

so you know that the vertex is somewhere above the x-axis

freckles · Answer

just draw the graph somewhere that fits the information given

freckles · Answer

also my notifications aren't working properly

anonymous · Answer

|dw:1421261705761:dw| So like this? @freckles

freckles · Answer

sounds good 
no-x intercepts
and open up
great job