Please help.

1. If 2x^2 + y^2 = −2 then evaluate (d^2y/dx^2) when x = 2 and y = 3.

2. Find (dy/dx) if f(x) = (x + 1)^2x.
a. 2xln(x + 1)
b. 2ln(x+1) + (2x/(x+1))
c. 2x(x + 1)(2x − 1)
d. [2ln(x+1) + (2x/(x+1)](x+1)^2x

Please check these answers:

3. Find y' if x = cos(y).
For my answer I got: −sin^2(y)

4. Find the slope of the graph of the relation y^3 − xy = −6 at the point (7, 2).
For my answer I got: 2/5

Question

Please help.

1. If 2x^2 + y^2 = −2 then evaluate (d^2y/dx^2) when x = 2 and y = 3.

2. Find (dy/dx) if f(x) = (x + 1)^2x.
a. 2xln(x + 1)
b. 2ln(x+1) + (2x/(x+1))
c. 2x(x + 1)(2x − 1)
d. [2ln(x+1) + (2x/(x+1)](x+1)^2x

Please check these answers:

3. Find y' if x = cos(y).
For my answer I got: −sin^2(y)

4. Find the slope of the graph of the relation y^3 − xy = −6 at the point (7, 2).
For my answer I got: 2/5

anonymous · Answer

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anonymous · Answer

Any help would be much appreciated!

anonymous · Answer

@Lyrae @TheSmartOne @myininaya @CausticSyndicalist

anonymous · Answer

$$2x^2 + y^2 = −2\
4x+2yy'=0$$$$y'=-\frac{2x}{y}$$

anonymous · Answer

@satellite73 okay yes got that far then i do

anonymous · Answer

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