Question

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is



(x - 4)² + y² = 2√3

(x - 4)² + y² = 12

(x + 4)² + y² = 12

Answer 1

@AlexandervonHumboldt2

Answer 2

(x-a)^2+(y-b)^2=r^2 where (a, b) center r raidus
(x - 4)² + y² = 12

Answer 3

thnx:)