Mathematics
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OpenStudy (anonymous):
PLEASE HELP WILL GIVE MEDAL, FAN, AND TESTIMONIAL!
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OpenStudy (anonymous):
OpenStudy (anonymous):
15%
OpenStudy (anonymous):
@Brostep0s @BunnyBree @Deadpool. @Joel_the_boss @TheSmartOne
OpenStudy (anonymous):
can you help me with 3 more?
OpenStudy (anonymous):
I agree it is 15 percent increase because 90-75=15... The percent of increase is equal to the percent subtracted from the totals
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OpenStudy (anonymous):
The answer is %15 or D
OpenStudy (anonymous):
OpenStudy (anonymous):
That is the same screenshot
OpenStudy (anonymous):
If you could give us a new one than I would be happy to help
OpenStudy (anonymous):
D
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OpenStudy (anonymous):
medal?
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
ops i posted the same one twice my mistake
OpenStudy (anonymous):
OpenStudy (anonymous):
@randypolle
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OpenStudy (anonymous):
still the same attachment
OpenStudy (anonymous):
what the heck! lol hold on
OpenStudy (anonymous):
OpenStudy (anonymous):
@randypolle
OpenStudy (anonymous):
@Blkknight217
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OpenStudy (anonymous):
The answer is 12% because
12 X 36.50 =4.38
and 36.50-4.38= 32.12
OpenStudy (anonymous):
So the answer is B or the second choice
OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
The answer is a ten percent decrease because
20-18= 2
2 ÷ 20 = .1
.1 X 100 = 10
The answer is a 10% decrease
OpenStudy (anonymous):
May I have that medal and fan now?
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OpenStudy (anonymous):
@Blkknight217
OpenStudy (anonymous):
Or do you have any more that need answering?
OpenStudy (anonymous):
@chosenmatt
OpenStudy (anonymous):
i have one more and i faned you already lol
OpenStudy (anonymous):
omg this is lagging so much the things i put like 10 minutes ago are not coming out like if i posted it right now sorry about that
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OpenStudy (anonymous):
OpenStudy (anonymous):
The answer is a 50% increase as
$4.50 - $3.00 = $1.50
1.50 ÷ 3 = 0.5
0.5 X 100 = 50%
OpenStudy (anonymous):
Hope I was a help... @js7474
OpenStudy (anonymous):
ya sorry my computer decided to stop working yesterday but ya you were a great help! @Blkknight217