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OpenStudy (anonymous):
Please help! Will fan and medal!!!
Jayden and Alexa were asked if 6C2 + 6C3 = 7C3 is true. Their calculations showed it was not true, but they both made mistakes in their calculations. Explain and correct their mistakes.
I already corrected jaydens mistakes, but i cant figure out how to fix Alexa's. So please help.
Alexa added the fractions by using the LCD (least common denominator).
Ill type her work in the comments
11 years ago
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OpenStudy (anonymous):
Step 1 6! 6!
--- + ---
2!4! 3!3!
Step 2 6! 4*6!
---- + -----
4*3!3! 4*3!3!
Step 3 5*6!
------
4*3!3!
Step 4 7! 7*6!
---- = -----
3!4! 4*3!3!
Step 5 5*6! 7*6!
----- not equal -----
4*3!3! 4*3!3!
11 years ago
OpenStudy (anonymous):
what sorcery is this???
11 years ago
OpenStudy (anonymous):
@KissMyAxe
the worst kind..Algebra
11 years ago
OpenStudy (anonymous):
where is the working of the other sorcerer
11 years ago
OpenStudy (anonymous):
@madison.bush
11 years ago
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OpenStudy (anonymous):
what other sorcerer? @KissMyAxe
11 years ago
OpenStudy (anonymous):
Alexa
11 years ago
OpenStudy (anonymous):
That was alexa's haha
@KissMyAxe
11 years ago
OpenStudy (anonymous):
OH!
11 years ago
OpenStudy (anonymous):
well lets see......
11 years ago
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OpenStudy (anonymous):
step 2 is wrong
11 years ago
OpenStudy (anonymous):
Yeah..i thought so.. so how do i fix it? @KissMyAxe
11 years ago
OpenStudy (anonymous):
for the first fraction, instead of 4 multiply it by 4/3
11 years ago
OpenStudy (anonymous):
and for the second don't multiply it by 4
11 years ago
OpenStudy (anonymous):
leave this! this gives me headache
11 years ago
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OpenStudy (anonymous):
well what do i do for the second one @kissmyaxe
11 years ago
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