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Mathematics 12 Online
OpenStudy (anonymous):

Tan^2 theta = 1/3

OpenStudy (anonymous):

can you please use the equation buttom n rewrite it please

OpenStudy (michele_laino):

please note that we have: \[\tan \theta =\pm \frac{ 1 }{ \sqrt{3} }\]

OpenStudy (michele_laino):

so you have to solve two distinct trigonometric equations

OpenStudy (michele_laino):

namely th first equation is: \[\tan \theta =\frac{ 1 }{ \sqrt{3} } \] and he second equation, is: \[\tan \theta =-\frac{ 1 }{ \sqrt{3} } \]

OpenStudy (michele_laino):

oops...namely the first equation..... ...and the second equation...

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