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can some one help me with finding an angle between two vectors
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\[u=<2,-4>, v=<3,-8\]
i already got here \[\cos \left( \theta \right) = \frac{ 6+32 }{ \sqrt{20}\times \sqrt{73}}\]
\[\theta = \cos^{-1} \frac{ 6+32 }{ \sqrt{20}x \sqrt{73} }\]
OMG THANK YOU SO MUCH
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now i have .1048
do i multiply this by 360
That is probably in radians. You need to convert to degrees.
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