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Mathematics 10 Online
OpenStudy (anonymous):

can some one help me with finding an angle between two vectors

OpenStudy (anonymous):

\[u=<2,-4>, v=<3,-8\]

OpenStudy (anonymous):

i already got here \[\cos \left( \theta \right) = \frac{ 6+32 }{ \sqrt{20}\times \sqrt{73}}\]

OpenStudy (anonymous):

\[\theta = \cos^{-1} \frac{ 6+32 }{ \sqrt{20}x \sqrt{73} }\]

OpenStudy (anonymous):

OMG THANK YOU SO MUCH

OpenStudy (anonymous):

Welcome

OpenStudy (anonymous):

now i have .1048

OpenStudy (anonymous):

do i multiply this by 360

OpenStudy (anonymous):

That is probably in radians. You need to convert to degrees.

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