Question

Find the domain, range and vertex of the following parabola. y=x^2-14x+44 Show all work.

Answer 1

First you need to put that standard form quadratic to vertex form

Answer 2

Know how to do that?

Answer 3

Not really, sorry.

Answer 4

Ok.

standard form

was x^2-14x+44

you need to complete the square.

start by subtracting the value of c (44)

y-44=x^2-14x

now, complete the perfect square trinomial. use the formula (b/2)^2

(-7)^2=49

add that to both sides

y+5=x^2-14x+49

simplify to

y+5=(x-7)^2

y=(x-7)^2

Answer 5

y=(x-7)^2-5

to get the vertex from this, get the number from inside the parenthesis, switch the sign, and -5 will be the y value.

vertex: 7,-5

Answer 6

got that?

Answer 7

im still here :)