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If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point (5, 6). True False
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@AlexandervonHumboldt2
so true?
\(\large\color{slate}{ (x - 2)^2 + (y - 6)^2 = 4 }\) substitution, \(\large\color{slate}{ (\color{blue}{5} - 2)^2 + (\color{blue}{6} - 6)^2 = 4 }\)
5-2 is not 2, it is 3. Looks like you were thinking that 2^2 is 4. and that is true, but 3^2 is not 4...
ohh thats what i did wrong
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thnx
so was i rigt?
your answer is?
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