Question

Will medal, solve the equation 4sin theta - sqrt 3 = 2sin theta. express in radian measure.

Answer 1

\[4\sin(\theta) - \sqrt{3}= 2 \sin(\theta)\]

that righ

Answer 2

Or is there a parenthesis around (theta - sqrt 3)

\[4\sin(\theta-\sqrt{3}) = 2\sin(\theta)\]

Answer 3

first one is correct, no parenthesis @danjs