medal and honor Solve. 6(a + 3) = 18 + 6a (Points : 1) no solution all real numbers –3 –1
all are real numbers
no solution
wuuuut
i solve it gave me all as real numbers
No.
6(a + 3) = 18 + 6a Distribute: 6a + 18 = 18 + 6a Apply commutative property to right side: 6a + 18 = 6a + 18 Subtract 6a and 18 from both sides: 0 = 0 Since 0 = 0 is a true statement, that means this equation is true for all real numbers.
but that also means no solution
well at least thats what i learned
@prguan You solved the equation correctly and got 0 = 0. Your only mistake was reaching the wrong conclusion.
ohhhhhh i get it
You can't have learned that because it's incorrect. What you learned was a similar thing you are now confusing with.
whoops
There is no solution is the variables are eliminated and the statement is false.
then indefinitely many solutions
which also means all real numbers?
For example: 6(a + 3) = 15 + 6a 6a + 18 = 15 + 6a 18 = 15 Since we have a false statement, there is no solution.
Yes. Infinite number of solutions means the same as all real numbers.
oh ok i thought it indefinitely many solutions but didn't know it as all real numbers
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