Question

Please help!!! Last HW question, and I cannot figure it out!!! Will medal if given good help and an explanation!!

Find the equations of the lines through the point (3, 8) that are parallel to and perpendicular to the line y = 3x + 8. Use y as the dependent variable.

Answer 1

@mathstudent55 please help me, I have an hour to submit, and have been finished with every other problem for 45 min...

Answer 2

confirm your question please

Answer 3

perpendicular lines have negative reciprocal slopes....y = 3x + 8

what is the slope of this line?
what is the neg reciprocal of that?

Answer 4

Using the equation y=3x+8 find a parallel and perpendicular line going through the point (3,8)

Answer 5

ok

Answer 6

I know what the parallel and perpendicular lines would be of that equation, its getting the line of the equation to go through the point i cannot do

Answer 7

with the slope and the given point...use point slope form to get new line

y - y1 = m(x-x1)

Answer 8

ok, so y-8=-1/3(x-3) ?

Answer 9

y=-1/3x+9

Answer 10

yes...that is the perpendicular line

Answer 11

now for the parallel line..same slope plug slope and point into formula point slope

Answer 12

and so for the parallel one, just do the same thing with m=3?

Answer 13

yes..and the given point

Answer 14

ok, thanks!! I think it would be y=3x-1

Answer 15

correct

Answer 16

Thanks!!!

Answer 17

uw