2C3H8O + 9O2=6CO2 + 8H2O

Use the above reaction to solve the following problems. Show work if you can.

1. What type of reaction is this?

2. If you started with 5.0 moles of O2 and excess C3H8O, how many moles of water could be formed?

3. If you started with 5.1 moles of O2 and 1.2 moles of C3H8O, how many moles of water could be formed? Identify the limiting reactant, and then calculate the water moles based on that.

4. If you started with 62g of C3H8O and 31g of O2, what would your limiting reactant be? How may grams of CO2 could be formed under these circumstances?

Question

2C3H8O + 9O2=6CO2 + 8H2O

Use the above reaction to solve the following problems. Show work if you can.

1. What type of reaction is this?

2. If you started with 5.0 moles of O2 and excess C3H8O, how many moles of water could be formed?

3. If you started with 5.1 moles of O2 and 1.2 moles of C3H8O, how many moles of water could be formed? Identify the limiting reactant, and then calculate the water moles based on that.

4. If you started with 62g of C3H8O and 31g of O2, what would your limiting reactant be? How may grams of CO2 could be formed under these circumstances?

butterflydreamer · Answer

Can you see that the product is Carbon Dioxide ( CO2) and Water (H2O)?
This means that it is a complete combustion reaction.