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Algebra 8 Online
OpenStudy (anonymous):

Instructions:Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Mark’s garden is a rectangle that is 4a+96a+15 meters long and 4a+24a+15 meters wide. If Mark decides to fence his garden, the total length of fencing material required would be ________ meters. If he uses prebuilt fence sections that are 50 centimeters wide, he will need ________sections.

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

You're finding the perimeter of the garden. (4a+96a+15)+(4a+24a+15). To start you'll combine like terms. (128a+30). That is the perimeter of the rectangle, since we have no value for a. So, If mark decideds to fence his garder, the total length of fencing material required would be 128a+30 meters, and if he uses prebuilt sections, he will need (128a+30)/50

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