Question

FAN AND MEDAL, HELP PLEASE? =)
multiplication involving binomials and trinomials in one variable;
(7u+3)(2u^2-6u-1)
simplify.

Answer 1

7u+3(2u^2)= 14u^3+6u^2
7u+3(-6u)= -42u^2-18u
7u+3(-1)= -7u-3

14u^3+6u^2-42u^2-18u-7u-3

14u^3-36u^2-25u-3 ?

Answer 2

You have to do long division to complete these.

Ex. (2x + 1) (3x^2 + 2x - 1)

2x + 1 | (4X^2 + 2x - 1)

1.) 2x times what gives you 4x^2? = 2x
So put 4x^2 under the 4x^2. (they'll cancel out when subtracting).

2.) Now, what is 2x times 1? = 2x. So put + 2x beside the number you just wrote.

3.) Subtract them. The first numbers should cancel out, then you'll have a remainder with the other one. Then drop down the 2x from the trinomial:

Just repeat that until there aren't anymore numbers to drop down.

Answer 3

thank you! i'll try it haha I've never been good at math =/